Design

1. A floor framing consists of the following: hardwood floor (4 psf), 1 in. plywood (3 psf), 2 in. × 12 in. framing at 4 in. on center (2.6 psf), ceiling supports (0.5 psf), and gypsum wallboard ceiling (5 psf). Determine the floor dead load.

2. In Problem 2.1, the floor covering is replaced by a 1 in. concrete slab and the framing by 2 in. × 12 in. at 3 in. on center.

Determine the floor dead load. Hint: Weight in pounds of concrete/unit area = 1 ft × 1 ft × 1/12 ft × 150. 3. For the floor framing plan of Example 2.2, determine the design live load on the interior beam BC.

Solution: